Question

Log2(x+5)-log2(x-3)=2​

Answer 1

$log_{2}(x+5) - log_{2}(x-3) = 2 \\ log_{2} \frac{x + 5}{x - 3} = 2$

2= log2 (4) ,pois 2²=4

$log_{2} \frac{x + 5}{x - 3} = log_{2}(4)$

$\frac{x + 5}{x - 3} = 4 \\ x + 5 = 4(x - 3) \\ x + 5 = 4x - 12 \\ 3x = 17 \\ x = \frac{17}{3}$

x=17/3

Answer 2

$Olá!!$

$Log_{2}(x+5)-Log_{2}(x-3)=2$

$Log_{2}\frac{x+5}{x-3}=2$

$\frac{x+5}{x-3}=2^2$

$x+5=(x-3).4$

$x+5=4x-12$

$x-4x=-12-5$

$-3x=-17$

$x=\frac{-17}{-3}$

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