Question

x2+4x-12=0

preciso urgente ​

Answer 1

x²+4x-12=0

Δ= b²-4.a.c

Δ= 4² - 4.1.(-12)

Δ=36 + 48

Δ= 64

Bhaskara: -b√Δ / 2a

-4±8 / 2.1

x'= -4+8 ÷2= 2

x"= -4-8 ÷ 2= -6