• Matéria: Matemática
  • Autor: Rogercosta22
  • Perguntado 7 anos atrás

Desenvolva o binômio (a+10) elevado a 6

Respostas

respondido por: ellenmayra272921
1

Resposta:

(x-2)^6 = X^6 - 6*2X^5 + 15*4X^4 - 20*8 X^3 + 15*16 X^2 - 6*32X + 64

espero ter ajudado

respondido por: Anônimo
0

Resposta:

(a+10)^6

(a+10)(a+10)(a+10)(a+10)(a+10)(a+10)

(a³+3(a)²10+3a(10)²+(10)³)(a³+3(a)²10+3a(10)²+(10)³)

(a³+30a²+300a+1000)(a³+30a²+300a + 1000) =

a^6+30a^5+300a⁴+1000a³+30a^5+900a⁴+9000a³+30 000a²+300a⁴+9000a³+90 000a²+300000a +1000a³+30000a²+300000a + 1000000 =

a^6+30a^5+30^5+300a⁴+900a⁴+300a⁴+1000a³+9000a³+9000a³+1000a³+30000a²+90000a²+30000a²+300000a+300000a+1000000=

a^6+60^5+1500a⁴+20000a³+150000a²+600000a+1000000

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