Question

(2 elevado ao cubo . 2 elevado 5 . 2 elevado 6 ) : 2 ela do a 7

Answer 1

$( {2}^{3} . {2}^{5} . {2}^{6} ) \div {2}^{7} \\ \ =( \ {2}^{3 + 5 + 6} )\div {2}^{7} \\ = {2}^{14} \div {2}^{7} = {2}^{14 - 7} = {2}^{7}$