Question

Calcule a distancia entre pontos A(1,5) e B(3,11)

Answer 1

Resposta:

d²=(x1-x2)²+(y1-y²)²

d²=(1-3)²+(5-11)²

d²=(-2)²+(-6)2

d²=4+36

d²=40

d=√40 = √(2²*10) =2√10 unidade de distância

Answer 2

$\large\boxed{\begin{array}{l} \sf{d_{AB }=\sqrt{(x_{A} -x_{B})^{2}+(y_{A} -y_{B})^{2}}} \\ \sf{d_{AB } = \sqrt{(1 - 3) {}^{2} + (5 - 11) {}^{2} } } \\ \sf{d_{AB } = \sqrt{ ( - 2) {}^{2} + ( - 6) {}^{2} }} \\ \sf{d_{AB } = \sqrt{4 + 36} } \\ \sf{d_{AB } = \sqrt{40} } \\ \huge \boxed{ \boxed{ \boxed{ \boxed{ \sf{d_{AB } = 2 \sqrt{10} }}}}}\end{array}}$