Question

Me ajudem por favor!

Resolva as equações de 2 grau usando a formula de bhaskara

A)x^2-6x+8=0
B)x^2-4x+3=0
C)x^2-15x+50=0
D)x^2+x-2=0
E)x^2+x-12=0
F)x^2+3x+2=0
G)x^2+9x+20=0
H)x^2+8x+7=0
I)x^2-7x-30=0
J)x^2-2x+1=0
K)x^2-8x+16=0
L)x^2-5x-14=0
M)2x^2-14+12=0

Answer 1

Resposta:

Respondendo a letra b . . .

$B) x^{2}-4x+3=0$

Δ = b² - 4 × a × c

Δ = 4² - 4 × 1 × 3

Δ = 16 - 12

Δ = 4

$x'=\frac{-b+\sqrt{delta}}{2*a}\\x'=\frac{-(-4)+\sqrt{4}}{2*1}\\x'=\frac{4+2}{2}\\x'=\frac{6}{2}\\x'=3\\\\x"=\frac{-b-\sqrt{delta}}{2*a}\\x"=\frac{-(-4)-\sqrt{4}}{2*1}\\x"=\frac{4-2}{2}\\x"=\frac{2}{2}\\x"=1$

$B)(3,1)$

Calculo mental;

$A](4,2)\\B](3,1)\\C](10,5)\\D](1,-2)\\E](3,-4)\\F](-1,-2)\\G](-4,-5)\\H](-1,-7)\\I](10,-3)\\J](1,1)\\K](4,4)\\L](7,-2)\\M](6,1)$

Explicação passo-a-passo: