Question

Resolva as equações literais na incógnita x:
x^2-(a+b)x+ab=0​

Answer 1

Resposta: {a,b}

x² - (a+b)x + ab = 0

a = 1

b = - (a+b)

c = ab

Δ = b² - 4ac

Δ = [-(a+b)]² - 4.1. ab

Δ = a² + 2ab + b² - 4ab

Δ = a² - 2ab + b²

Δ = (a-b)²

x' = (-b⁺/₋√Δ)/2a

x' = [(a + b) + √(a-b)²]/2.1

x' = [(a+b)+(a-b)]/2

x' = [2a+0]/2

x' = 2a/2

x' = a

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x'' = [(a+b)-(a-b)]/2

x'' = [a+b-a+b]/2

x'' = 2b/2

x'' = b