Question

resolva a seguinte equacao do 2
(x+2)ao quadrado -4=0

Answer 1

(x+2)^2-4=0
x^2+2.x.2+2^2-4
x^2+4x+4-4
x^2+4x=0
delta=b^2-4ac
delta=4^2-4.1.0
delta=16-0
delta=16
x=-b-/+ raiz de delta/2a
x=-4-4/2.1
x=-8/2
x=-4
x=-4+4/2.1
x=0/2
x=0

Answer 2

(x + 2)² - 4 = 0
(x + 2)(x + 2) - 4 = 0
x² + 2x + 2x + 4 - 4 = 0
x² + 4x = 0
x(x + 4) = 0
x = 0
x + 4 = 0
x = -4

Raízes 0 e -4