Question

Ache o delta de : $-3x^{2}$ + 2x e encontre seu vertice.

Answer 1

Resposta:

P(x)=-3x²+2x

a=-3

b=2

c=0

Δ =b²-4*a*c = (2)² -4*(-3)*0 =4

Vértice=(vx,vy)

vx=-b/2a =-(2)/(-6)=1/3

vy=-Δ /4a =-4/(-12) =1/3