Question

x²-6x-7=0 genteeeee, ajudem ai kkkk ​

Answer 1

Resposta:

$x^{2}-6x-7=0\\delta=6^{2}-4*1*(-7)\\delta=36+28\\delta=64\\\\x'=\frac{-(-6)+\sqrt{64}}{2*a}\\x'=\frac{6+8}{2*1}=\frac{14}{2}=\boxed {7}\\\\x"=\frac{-(-6)-\sqrt{64}}{2*a}\\x"=\frac{6-8}{2*1}=\frac{-2}{2}=\boxed {-1}\\\\S(7,-1)$

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