Question

Como resolver:

a) -2x^2 + 100 = 0

b)4x^2 - 9 = 0

Answer 1

${ - 2x}^{2} + 100 = 0 \\ \\ x( - 2x + 100) \\ \\ x = 0 \\ \\ - 2x + 100 = 0 \\ \\ - 2x = - 100 \\ \\ x = \frac{100}{ - 2} \\ \\ \times = - 50$

b) 4x2=9

x2=9/4

x2=+ - 2

x= + - √2

S={-√2; √2}