Question

RESOLVA:

a) 5 x - 7 > 8 x + 3

b) x + 1 > 0

c) 3 ( 2 x + 1 ) - 3 x < 5 x - 1

d) 3 ( x - 2 ) + 2 ( x + 3 ) ≥ 2 x - 3 ( 2 x - 7 )


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Answer 1

a)

$5x - 7 > 8x + 3 \\ 5x - 8x > 3 + 7 \\ - 3 > 10$

$x < - \frac{10}{3}$

b)

$x + 1 > 0 \\ x > - 1$

c)

$3(2x + 1) - 3 < 5x - 1 \\ 6x + 3 - 3x < 5x - 1 \\ 3x + 3 < 5x - 1$

$3x - 5x < - 1 - 3 \\ - 2x < - 4 \\ x > 2$

d)

$3(x - 2) + 2(x + 3) \geqslant 2x - 3(2x - 7)$

$3x - 6 + 2x + 6 \geqslant 2x - 6x + 21$

$3x \geqslant - 6x + 21 \\ 3x + 6x \geqslant 21 \\ 9x \geqslant 21$

$x \geqslant \frac{7}{3}$