Question

Se sen x = 3V5/7, com II/2 <x<II. Determine y sabendo que y = 2 + sec x.​

Answer 1

Resposta:

y = 11/2

Explicação passo-a-passo:

sen x = 3V5/7, com II/2 <x<II. Determine y sabendo que y = 2 + sec x.

π/2 e π (2°Q)

sen x = 3V5/7

sen^2 x + cos ^2 x = 1

(3√5/7)^2 + cos^2 x = 1

(9.5/49)+ cos^2 x = 1

45/49 + cos^2 x = 1

cos^2 x = 1 - 45/49

cos^2 x = (49-45)/49

cos^2 x = 4/49

cos x = √4/49

Cos x = 2/7

Sec x = 1/cos x

Sec x = 1 : 2/7

sec x = 7/2

y = 2 + sec x

y = 2 + 7/2

y = (4+7)/2

y = 11/2