Question

respondam as equações urgente :
6y+3=5y-2

3(x-2) - (1-x) = 13

6(4-t) - 55= -5 (2t + 3)

5(-4x-1)=4x-3 (4x-1) -4

k-(3-k)=1

Answer 1

6y-5y=-2-3
y=-5

3(x-2)-(1-x)=13
3x-6 - 1-x=13
3x-x=13+7
2x=20
x=20/2 x=10

6(4-t) - 55=-5(2t+3)
24-6t - 55= -10t + 15
-6t+10t= 15+55-24
4t= 46
t= 46/4
t=11,5

5(-4x-1) = 4x-3(4x-1) -4
-20x-5 =4x - 12x+3 -4
-20x+12x+4x= 3 - 4 + 5
-20x +16x =4
-4x = 4
x=4/-4
x=-1

k-(3-k)=1
2k=1+3
k=4/2
k=2

Espero ter lhe ajudado...Bons estudossss ;*