Question

Dada a f(x)=-x2+3x+10​

Answer 1

Resposta:

f(x)=-x^2+3x+10

-x^2+3x+10=0

x^2-3x-10=0

∆= 9+40

∆=49

x=3+ou -√49/2

x=3+7/2

x'=10/2= 5

x"= 3-7/2

x"=-4/2

x"=-2

S= {-2,5}

Answer 2

Resposta:

x1 = -2

x2 = 5

Explicação passo-a-passo:

-x²+3x+10​

a=-1        

b=3

c=10

Δ=b²-4 · ac

Δ=3²- 4 · (-1) · 10

Δ=9+40

Δ=49

Bhaskara

x=-b±√Δ  

      2·a

x=-3±√49

 2·(-1)

x1 =-3+7   =   4   = -2

 -2          -2

x2 =-3-7   = -10    = 5

-2                -2

Prontinho!!