Question

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$log2(x) + log8(x) = 1$
determine o valor de X​

Answer 1

$log_{2}(x) + log_{8}(x) = 1 \\ log_{2}(x) + log_{ {2}^{ 3 } }(x) = 1 \\ log_{2}(x) + \frac{1}{3} log_{2}(x) = 1$

$\frac{3 log_{2}(x) + log_{2}(x) = 3 }{3} \\ 3 log_{2}(x) + log_{2}(x) = 3\\ 4 log_{2}(x) = 3\\ log_{2}(x) = \frac{3}{4}$

$x = {2}^{ \frac{3}{4} } \\ x= \sqrt[4]{2^3}$