Question

Seja f a função de R em R definida por f(x) = x² - 3x + 4, Calcular:
a) f (-1/3)
b) f (√3)
c) f (1 - √2)

Answer 1

E ae Mathews,

dada a função, $f(x)=x^2-3x+4$, podemos calcular f(-1/3); f√3 e f(1-√2):

$f\left(- \dfrac{1}{3}\right)=\left(- \dfrac{1}{3}\right)^2-3\left(- \dfrac{1}{3}\right)+4\\\\ f\left(- \dfrac{1}{3}\right)= \dfrac{1}{9}+1+4\\\\ \Large\boxed{\boxed{f\left(- \dfrac{1}{3}\right)= \dfrac{46}{9}~~ ou~~5 \dfrac{1}{9}}}$

$f( \sqrt{3})=( \sqrt{3})^2-3\cdot \sqrt{3}+4\\ f( \sqrt{3})=3-3 \sqrt{3}+4\\\\ \Large\boxed{\boxed{f( \sqrt{3})=7- 3\sqrt{3}}}$

$f(1- \sqrt{2})=(1- \sqrt{2})^2-3\cdot(1- \sqrt{2})+4\\ f(1- \sqrt{2})=3-2 \sqrt{2}-3+3 \sqrt{2}+4\\ f(1- \sqrt{2})=3-3-2 \sqrt{2}+3 \sqrt{2}+4\\\\ \Large\boxed{\boxed{f(1- \sqrt{2})=4+ \sqrt{2}}}$

Tenha ótimos estudos ;D

Answer 2

Resposta:

E ae Mathews,