Question

Me ajudem, pfvr, é urgente

Answer 1

$\sqrt{5}x^2+ \frac{3x}{2} =0 \\ D=( \frac{3}{2})^2-4. \sqrt{5}.0 \\ D= \frac{9}{4} \\ x= \frac{ -\frac{3}{2}+/- \sqrt{ \frac{9}{4} } }{2. \sqrt{5} } \\ \\ x_1= \frac{-1,5+1,5}{2 \sqrt{5}}=\ \textgreater \ \frac{0}{2 \sqrt{5} }=0 \\ \\ x_2= \frac{-1,5-1,5}{4,4}= (\frac{-3}{2 \sqrt{5} }). \sqrt{5}= \frac{-3 \sqrt{5} }{10}$