Question

Como resolvo essas duas... equações?​

Answer 1

Resposta:

1)

$\frac{x + 3}{2} + \frac{x + 4}{3} = \frac{x + 6}{6} \\ \frac{3(x + 3) + 2(x + 4)}{6} = \frac{x + 6}{6} \\ 3(x + 3) + 2(x + 4) = x + 6 \\ 3x + 9 + 2x + 8 = x + 6 \\ 3x + 2x - x = 6 - 9 - 8 \\ 4x = - 11 \\ x = - \frac{11}{4}$

2)

$3(x + 4) - 5(x - 1) = 6(x + 2) - 2(x + 5) \\ 3x + 12 - 5x + 5 = 6x + 12 - 2x - 10 \\ 3x - 5x - 6x + 2x = 12 - 10 - 12 - 5 \\ - 6x = - 15 \\ 6x = 15 \\ x = \frac{15}{6} \\ x = \frac{15 \div 3}{6 \div 3} \\ x = \frac{5}{2}$