Question

calcule o determinante de cada matriz ​

Answer 1

a)

det A = 2(1 • (–1) – (–1) • 2) – (3 • 2 – 1 • 1)

det A = 2(–1 + 2) – (6 – 1)

det A = 2 – 5 = –3

b)

det B = 1 • (–2) – (–1) • 2 = –2 + 2 = 0

c)

det C = 3(4 • 1 – (–1/2) • 2) + (–2 • 2 – 4 • 5)

det C = 3(4 + 1) + (–4 – 20)

det C = 15 – 24 = –9

d)

det D = 5 • 2/5 – 1/3 • (–9) = 2 + 3 = 5