Question

(2x+3y)² por favor caculo completo​

Answer 1

$\left(2x+3y\right)^2\\ \mathrm{Aplicar\:Formula\:do\:Quadrado\:Perfeito}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\ a=2x,\:\:b=3y\\ =\left(2x\right)^2+2\cdot \:2x\cdot \:3y+\left(3y\right)^2\\ \mathrm{Simplificar}\:\left(2x\right)^2+2\cdot \:2x\cdot \:3y+\left(3y\right)^2:\quad 4x^2+12xy+9y^2\\ \left(2x\right)^2+2\cdot \:2x\cdot \:3y+\left(3y\right)^2$

$\left(2x\right)^2=4x^2\\ \left(2x\right)^2\\ \mathrm{Aplicar\:as\:propriedades\:dos\:expoentes}:\quad \left(a\cdot \:b\right)^n=a^nb^n\\ =2^2x^2\\ 2^2=4\\ =4x^2\\ 2\cdot \:2x\cdot \:3y=12xy\\ 2\cdot \:2x\cdot \:3y\\ \mathrm{Multiplicar\:os\:numeros:}\:2\cdot \:2\cdot \:3=12\\ =12xy\\ \left(3y\right)^2=9y^2\\ \left(3y\right)^2\\ \mathrm{Aplicar\:as\:propriedades\:dos\:expoentes}:\quad \left(a\cdot \:b\right)^n=a^nb^n\\ =3^2y^2\\ 3^2=9\\ =9y^2$

$=4x^2+12xy+9y^2$