Question

2) Calcule as seguintes equações:
a) x2 - X - 12 = 0
b) x2 + 2x - 24 = 0
c) x2 + 2x - 8 = 0
d) x2 - 10x + 24 = 0

Answer 1

Resposta:

A primeira eu fiz completa, as outras não, mais acredito que dar para resolver através da primeira!

Explicação passo-a-passo:

$a)x^2-x-12=0, \ a=1 \ b=-1 \ c=-12\\\Delta=b^2-4*a*c\\\Delta=(-1)^2-4*1*(-12)\\\Delta=1+48\\\Delta=49\\\\x=\frac{-b^+_-\sqrt{\Delta} }{2*a} \\\\x=\frac{1^+_-7}{2}= x'=4 \ e \ x"=-3\\\\b)x^2+2x-24=0\\\Delta=2^2-4*1*(-24)\\\Delta=4+96\\\Delta=100\\\\x=\frac{-2^+_-10}{2}= x'=4 \ e \ x"=-6$

$c)x^2+2x-8=0\\\Delta=2^2-4*1*(-8)\\\Delta=4+32\\\Delta=36\\\\x=\frac{-2^+_-6}{2}= x'=2 \ e\ x"= -4$

$d)x^2-10x+24=0\\\Delta=(-10)^2-4*1*24\\\Delta=100-96\\\Delta=4\\\\x=\frac{10^+_-2}{2}= x'=6 \ e \ x" = 4$