Question

consideres as funções f(x)=x2+3x-6. os valores de f(0), f(2), f(-1) e f(5), são, respectivamente:​

Answer 1

F(0)=0•2+3•0-6
F(0)=-6
F(2)=2•2+3•2-6
F(2)=4+6-6
F(2)=4
F(-1)=-1•2+3•(-1)-6
F(-1)=-1-3-6
F(-1)=-11
F(5)=5•2+3•5-6
F(5)=10+15-6
F(5)=19