Question

preciso do cálculo dessa questão urgenteee

Answer 1

a = a' + a"

temos tg(45) = h/a' = 1

a' = h

tg(60) = h/(a - h)

√3 = h/(a - h)

sen(60) = h/2

√3/2 = h/2

h = √3

√3 = h/(a - h)

√3 = √3/(a - √3)

a - √3 = 1

a = 1 + √3

Answer 2

cos 60° = BD/AB

1 / 2 = BD / 2

2BD = 2

BD = 1m

AB^2 = h^2 + BD^2

2^2 = h^2 + 1^2

4 = h^2 + 1

h^2 = 3

h = √3m

tg 45° = h/DC

1 = √3/DC

DC = √3m

a = BD + DC

a = 1 + √3

Resp: a = (1+√3)m