Question

${(2}^{x} ) ^{x + 4 } = 32$
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Answer 1

(2^x)^x+4=32

2^x²+4x=2^5

x²+4x=5

x²+4x-5=0

Δ=b²-4ac

Δ=16-4.1.(-5)

Δ=36

x=-b+-√Δ/2a

x1=-4+6/2

x1=1

x2=-4-6/2

x2=-10/2

x2=-5

S={-5,1}