Question

Sendo f(x) = √x − 2 determine dy /dx :

Answer 1

Resposta:

f'(x)=dy/dx

Se for f(x) = √(x-2)

f'(x)=(1/2) * (x-2)^(-1/2)   * (x-2)'

f'(x)=1/[2√(x-2)]  * 1

f'(x)=1/[2√(x-2)]

Se  for  f(x) =√x − 2

f'(x) =(1/2)*x^(1/2-1)  - 0

f'(x) =1/[2√x]