Question

encontre o valor de x e y​

Answer 1

$\sin30^{\circ} = \dfrac{x}{12} \\ \dfrac{1}{2} = \dfrac{x}{12} \\ 2x = 12 \\ x = \dfrac{12}{2} = 6$

$\tan(30^{\circ} ) = \frac{6}{y} \\ \dfrac{ \sqrt{3} }{3} = \dfrac{6}{y} \\ y = \dfrac{18}{ \sqrt{3} } = \dfrac{18 \sqrt{3} }{3} = 6 \sqrt{3}$