Question

Resolva pela forma de bhaskara
a) x²-4x-12=0

Answer 1

x^2-4x-12=0
delta=b^2-4ac
delta=(-4)^2-4.1.(-12)
delta=16+48
delta=64
x=-b-/+ raiz de delta/2a
x=-(-4)-8/2.1
x=4-8/2
x=-4/2
x=-2
x=-(-4)+8/2.1
x=4+8/2
x=12/2
x=6

Answer 2

x² - 4x - 12 = 0
a=1, b=-4, c=-12
Δ = (-4)² · 1 · (-12)
Δ = 16 + 48
Δ = 64

x' = 4 + √64 / 2 · 1
x' = 4 + 8 / 2
x' = 12 / 2
x' = 6

x" = 4 - 8 / 2
x" =  -4 / 2
x" = -2