Question

qual o volume nescessário para armazenar 50g de gás carbônico​

Answer 1

$\mathsf{CO_{2}=12+2.16=44g/mol}$

$\mathsf{44\rightarrow\,22,4L}\\\mathsf{50\rightarrow\,x}$

$\boxed{\boxed{\mathsf{x=\dfrac{50\times22,4}{44}=25,45L}}}$