• Matéria: Matemática
  • Autor: giimarques
  • Perguntado 7 anos atrás

URGENTEEEE!!!!!
Cotg x - sen 2x =0

Respostas

respondido por: mends0608
0

Resposta:

Explicação passo-a-passo:

cotgx-sen2x=0\\cotgx=sen2x\\\\\dfrac{cosx}{senx}=2senxcos\\\\\\cosx=2sen^2x*cosx\\\\\dfrac{cosx}{cosx}=2sen^2x\\\\\\1=2sen^2=\\sen^2x= \dfrac{1}{2}\\\\senx= \mp \sqrt{\dfrac{1}{2}}\\\\senx = \mp \dfrac{\sqrt{2}}{2}\\x= \dfrac{\pi}{4}+\dfrac{k*\pi}{2}, k \in \mathbb{Z}

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