Question

quais as raizes da equacao: -x²+ x + 12 : 0​

Answer 1

Δ = b^{2} - 4ac

Δ = (1)^{2} - 4(1)(+12)

Δ = 1 + 48

Δ = 49

 

x = -b±√Δ / 2a

 

x = -1 ± 7 / 2

 

x' = -1 + 7 / 2 = -3

x'' = -1 - 7 / 2 = 4