Question

$\sqrt[2]{27}$ =
$\sqrt{9}$ - $\sqrt{81}$ =
$\sqrt{25}$ + $\sqrt{144}$ ÷ $\sqrt{1}$ =
$\sqrt[2]{8} }$ - $\sqrt{64}$ =
$\sqrt{16}$ + $\sqrt{4}$ =

Answer 1

Resposta:

a) 3$\sqrt{3}$

b)$\sqrt[2]{3^{2} }$-$\sqrt[2]{3^{2} } 3^{2}$ = 3 - 3 × 3 = 3 - 9 = -6

c)Nn consigo fazer essa

d)$\sqrt[2]{2^{2} } . 2 - \sqrt[2]{2^{2} } . 2^{2} . 2^{2}$ = $2\sqrt{2}$ - 2 × 2 × 2 = $2\sqrt{2}$ - 8

e) $\sqrt[2]{2^{2} } 2^{2} + \sqrt[2]{2}^{2}$ = 2 × 2 + 2 = 4 + 2 = 6