Question

calcule a raiz da rquaçao x^2+2x-35=0​

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+2x-35=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=2~e~c=-35\\\\\Delta=(b)^{2}-4(a)(c)=(2)^{2}-4(1)(-35)=4-(-140)=144\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(2)-\sqrt{144}}{2(1)}=\frac{-2-12}{2}=\frac{-14}{2}=-7\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(2)+\sqrt{144}}{2(1)}=\frac{-2+12}{2}=\frac{10}{2}=5\\\\S=\{-7,~5\}$

Answer 2

x^2+2x-35=0

delta=b^2-4ac

delta=2^2-4.1.(-35)

delta=4+140

delta=144

x=-b-/+ raiz de delta/2a

x=-2-12/2.1

x=-14/2

x=-7

x=-2+12/2.1

x=10/2

x=5