Question

resolução da equação x² -7x + 12 + 0

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-7x+12=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-7~e~c=12\\\\\Delta=(b)^{2}-4(a)(c)=(-7)^{2}-4(1)(12)=49-(48)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-7)-\sqrt{1}}{2(1)}=\frac{7-1}{2}=\frac{6}{2}=3\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-7)+\sqrt{1}}{2(1)}=\frac{7+1}{2}=\frac{8}{2}=4\\\\S=\{3,~4\}$

Answer 2

Resposta: s={3;4}

1. Explicação passo-a-passo: -7x+12=0

A=1   B=-7    C=12

Δ=b2-4ac

Δ=(-7)2-4.1.12

Δ=49-48

Δ=1

x=-b±√Δ/2a

x=-(-7)±√1/2.1

x=7±1/2

x1=7+1/2  =8/2 =4

x2=7-1/2  =6/2  =3    

s={3;4}