Question

$\sqrt{1} +( \sqrt{3} + \sqrt{27})^{2}  a) 1+ \sqrt{3}$

b)$\sqrt{7}$

c) 7

d) $\sqrt{27}$

e) 8

Answer 1

$1 +( \sqrt{3} + \sqrt{27})^{2} = 1 + (3 +2 \sqrt{3*27} + 27)$

$1 + (3 +2*9 + 27) = 1+(30+18) = 49$

Resposta: 49

Espero ter ajudado!

Answer 2

$\sqrt{1}+( \sqrt{3}+ \sqrt{27})^2= \\ \\ 1+( \sqrt{3})^2+2 \sqrt{3} \sqrt{27}+( \sqrt{27} })^2= \\ \\ 1+3+27+2 \sqrt{81} = \\ \\ 1+3+27+18=49$