Question

Resolva a seguinte derivada:
y=1/3x³-x+2

Answer 1

Façamos f =  u/v

Neste caso:

$f'=\frac{u'v-uv'}{v^2} \\ \\ u = 1 \\ u' = 0 \\ v= 3x^3 -x+1 \\ v'=9x^2-1 \\ \\ f'(x)=\frac{0.(3x^3-x+1)-1(9x^2-1)}{(3x^3-x-1)^2} \\ \\ \boxed{f'(x)=\frac{-(9x^2-1)}{(3x^3-x-1)^2}}$