Question

a) $\sqrt[3]{128}+\sqrt[3]{250}-\sqrt[3]{54}$

b) $\sqrt[3]{2} vezes \sqrt[3]{3}vezes\sqrt[3]{18}$

Answer 1

Resposta:

$\sqrt[3]{128} + \sqrt[3]{250} - \sqrt[3]{54} \\ 4 \sqrt[3]{2} + 5 \sqrt[3]{2} - 3 \sqrt[3]{2} \\ 4 + 5 - 3 \sqrt[3]{2} \\ 6 \sqrt[3]{2} \\ \sqrt[3]{2} \times \sqrt[3]{3} \times \sqrt[3]{18} \\ \sqrt[3]{2 \times 3 \times 18} \\ \sqrt[3]{108} = 3\sqrt[3]{ {2}^{2} } =3 \sqrt[3]{4}$