Question

calcule as coordenadas do vertice da função polindmial dada 

 y=x2-3x+4

xy e yy

Answer 1

$x^2-3x+4=0\\\\a=1\\b=-3\\c=4\\\\Xv= \frac{-b}{2.a}\\\\Xv= \frac{-(-3)}{2.1}\\\\\boxed{Xv= \frac{3}{2}}\\\\\\\Delta=b^2-4.a.c\\\Delta=(-3)^2-4.1.4\\\Delta=9-16\\\Delta=-7$

$Yv= \frac{-\Delta}{4.a}\\\\ Yv= \frac{-(-7)}{4.1}\\\\ \boxed{Yv= \frac{7}{4}}$

As coordenadas do Vértice são:

$\boxed{V=(~~ \frac{3}{2}~,~ \frac{7}{4} ~~)}$

Espero ter ajudado.. :)