Question

dados os números complexos Z1 = 1+2i, Z2 = -1 + 3i e Z3 = 2-2i, calcule :

(z1+z2) z3

Answer 1

$\boxed{\boxed{i^{2}=-1}}$

$(z_{1}+z_{2})*z_{3} = ([1+2i]+[-1+3i])*(2-2i)$
$(z_{1}+z_{2})*z_{3}=(1+2i-1+3i)*(2-2i)$
$(z_{1}+z_{2})*z_{3}=([1-1]+[2i+3i])*(2-2i)$
$(z_{1}+z_{2})*z_{3}=5i*(2-2i)$
$(z_{1}+z_{2})*z_{3}=5i*2-5i*2i$
$(z_{1}+z_{2})*z_{3}=10i-10i^{2}$
$(z_{1}+z_{2})*z_{3}=10i-10(-1)$
$(z_{1}+z_{2})*z_{3}=10i+10$
$(z_{1}+z_{2})*z_{3}=10+10i$

Answer 2

Dados os números complexos Z1 = 1+2i, Z2 = -1 + 3i e Z3 = 2-2i, calcule :

[(z1+z2)] (z3)
[(1+2i-1+3i)](2-2i)
(5i)(2-2i)
10i-10i²
10i+10