Question

3x-4+x²=0 quanto e ????​

Answer 1

Resposta:

x

2

−3x−4=0

a=1

b=−3

c=−4

Δ=b

2

−4ac

Δ=(−3)

2

−4(1)(−4)

Δ=9+16

Δ=25

\begin{lgathered}x=- \frac{b\pm \sqrt{\Delta} }{2a} = \frac{3\pm5}{2} \\ \\ x'= \frac{3+5}{2} = \frac{8}{2} =4 \\ \\ x"= \frac{3-5}{2} =- \frac{2}{2} =-1 \\ \\ \\ S=\{-1,4\}\end{lgathered}

x=−

2a

b±

Δ

=

2

3±5

x

′

=

2

3+5

=

2

8

=4

x"=

2

3−5

=−

2

2

=−1

S={−1,4}