Question

O Valor de E,Onde E = A7,3 + A3,2 - A5,4?

Answer 1

$An,p=n!/(n - p)!$
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$E = A7,3 + A3,2 - A5,4$
$E = [7! / (7-3)!] + [3!/(3-2)!]-[5!/(5-4)!]$
$E = (7! / 4!) + (3! / 1!) - (5! / 1!)$
$E=(7*6*5*4!/4!) + 3! - 5!$
$E=7*6*5 + 3*2*1 - 5*4*3*2*1$
$E = 210 + 6 - 120$
$E = 96$