Question

Quais sao as raizes da equacao x²-7x+6=0?

Answer 1

Resposta:

X' = 6; X'' = 1

Explicação passo-a-passo:

Δ = (-7)^2 - 4 x 1 x 6

Δ = 49 - 24

Δ = 25

x' = (- ( -7) + 5) /2 ---> x' = (7 + 5)/2 --->x' = 12/2 ---> x' = 6

x'' = (-(-7) - 5) / 2 ---> x'' = (7 -5)/2 ---> x'' = 2/2 ---> x'' = 1

Answer 2

Explicação passo-a-passo:

$\sf x^2-7x+6=0$

$\sf \Delta=(-7)^2-4\cdot1\cdot6$

$\sf \Delta=49-24$

$\sf \Delta=25$

$\sf x=\dfrac{-(-7)\pm\sqrt{25}}{2\cdot1}=\dfrac{7\pm5}{2}$

$\sf x'=\dfrac{7+5}{2}~\Rightarrow~x'=\dfrac{12}{2}~\Rightarrow~\red{x'=6}$

$\sf x"=\dfrac{7-5}{2}~\Rightarrow~x"=\dfrac{2}{2}~\Rightarrow~\red{x"=1}$