• Matéria: Matemática
  • Autor: mikaylanne18
  • Perguntado 6 anos atrás

calcule as potências a) (1/3)2 =b) (2/7)2 =c) (7/3)2 = d) (1/5)2 = e) (2/3)2 = f) (7/20)0 =g) (5/4)1 =h) (3/2)3 =i) (1/6)3 =j) (1/7)2 =k) (4/3)4 =l) (2/9)1 =m) ( 3/12)2 =n) (5/4)0 =o) (11/12)2 =p) (1/4)2 =q) (3/7)3 = Alguém me ajuda pfvr ​

Respostas

respondido por: gabialbino
10

Resposta:

a) (1/3)2 = 1/9

b) (2/7)2 = 4/49

c) (7/3)2 = 49/9

d) (1/5)2 = 1/25

e) (2/3)2 = 4/9

f) (7/20)0 = 1

g) (5/4)1 = 5/4

h) (3/2)3 = 27/8

i) (1/6)3 = 1/216

j) (1/7)2 =1/49

k) (4/3)4 = 256/81

l) (2/9)1 = 2/9

m) ( 3/12)2 = 1/16

n) (5/4)0 = 1

o) (11/12)2 = 121/144

p) (1/4)2 = 1/16

q) (3/7)3 = 27/343

Explicação passo-a-passo:

Exemplo:

(3/2)^3: 27/8

3*3*3= 27

2*2*2= 8

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