Question

CALCULE O X EM CADA UM DOS TRIÂNGULOS , ME AJUDEM POR FAVOR ​

Answer 1

Para resolver usamos as seguintes fórmulas.

Seno

$Sen(Ang)=\frac{cateto\ oposto\ a\ (Ang)}{hipotenusa}$

Cosseno

$Cos(Ang)=\frac{cateto\ adjacente\ a\ (Ang)}{hipotenusa}$

Tangente

$Tg(Ang)=\frac{cateto\ oposto\ a\ (Ang)}{cateto\ adjacente\ a\ (Ang)}$

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A)

$Cos(30)=\frac{x}{10}\\\\\frac{\sqrt{3} }{2} = \frac{x}{10} \\\\\frac{x}{10}=\frac{\sqrt{3}}{2}\\\\\frac{x}{10}\cdot \:10=\frac{\sqrt{3}}{2}\cdot \:10\\\\x=5\sqrt{3}$

B)

$Cos(45)=\frac{x}{10} \\\\\frac{\sqrt{2}}{2}=\frac{x}{10}\\\\\frac{x}{10}\cdot \:10=\frac{\sqrt{2}}{2}\cdot \:10\\\\x=5\sqrt{2}$

C)

$Sen(37)=\frac{x}{10}\\\\0.602=\frac{x}{10}\\\\\frac{x}{10}=0.602\\\\\frac{10x}{10}=0.602\cdot \:10\\\\x=6.02$

D)

$Tg(20)=\frac{x}{10} \\\\0.364=\frac{x}{10}\\\\\frac{x}{10}=0.36\\\\\frac{10x}{10}=0.364\cdot \:10\\\\x=3.64$