Question

ajudem-me
equação de 2° grau!

Answer 1

(x+1)^2=5x+41
x^2+2.x.1+1^2=5x+41
x^2+2x+1=5x+41
x^2+2x-5x+1-41
x^2-3x-40=0
delta=b^2-4ac
delta=(-3)^2-4.1.(-40)
delta=9+160
delta=169
x=-b-/+ raiz de delta/2a
x=-(-3)-13/2.1
x=3-13/2
x=-10/2
x=-5
x=-(-3)+13/2.1
x=3+13/2
x=16/2
x=8

Answer 2

$(x+1) ^{2} = 5x + 41 \newline x^2 + 2x + 1 = 5x + 41\newline x^2 + 2x +1 -5x - 41 = 0 \newline x^2 -5x - 40 = 0 \newline \\ \frac{x = -(-5) +ou- \sqrt{25+160}}{2*1} \\ \frac{x=5 +ou- \sqrt {185}} {2} \\ \frac{x'=5 + \sqrt{185}}{2}} \\ \\ \frac{x"=5-\sqrt{185}}{2}$