Question

me ajude pfvr x²+5x+6=0

Answer 1

x^2+5x+6=0
delta=b^2-4ac
delta=5^2-4.1.6
delta=25-24
delta=1
x=-b-/+ raiz de delta/2a
x=-5-1/2.1
x=-6/2
x=-3
x=-5+1/2.1
x=-4/2
x=-2

Answer 2

Aplica-se Bhaskara x = -b +ou- $\sqrt{delta}$ / 2a
Delta : b² - 4ac

Aplicando...

x² + 5x + 6 = 0 | a=1 b=5 c=6
Delta : 25 - 4.6 = 15 + 24 = 49

x= \frac{ -5 +ou- \sqrt{49} }{2} [/tex]
x= $\frac{-5 +ou- 7}{2}$
x'= $\frac{-5+7}{2}$ = $\frac{2}{2}$ = 1
x'' = $\frac{-5 -7}{2}$ = $\frac{-12}{2}$ = -6