Question

qual o valor de 4^2-log 9 na base 16?

Answer 1

Considerando log3 = 0,48 e log2 = 0,3
log 9 base 16 = log 9 base 10 / log16 base10

x = log 9 / log 16

x = log 3^2 / log 2^4

x = 2 log3 / 4 log2

x = 2 * 0,48 / 4 * 0,3

x = 0,96/1,2

x = 0,8

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Equação = 4^2 - x = 16 - 0,8 = 15,2
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