Question

calcule o valor de b na pg(b+3,b+17,b+59)

Answer 1

$\frac{b + 17}{b + 3} = \frac{b + 59}{b + 17} = \\\\ (b + 17)^{2} = (b + 3).(b + 59) = \\\\ b^{2} + 34b + 289 = b^{2} + 62b + 177 \\\\ 28b = 112\\ \boxed{b = 4}$