• Matéria: Matemática
  • Autor: vfilgueiracabral
  • Perguntado 6 anos atrás

RESOLVA

(20-3)+(7+5)=

50+{[15+(3-9)+1]}=

15-(7+2)-8=

18+(9-15)-8=

7-[4+(3-5)]=

{5-532-(50-20]}=

{16-[12+(20-25)]}=

10-{30+[4-(5+2)]}=

{-2+[3-0-(8+1)]-10}

URGENTEEEEE!!!!


Respostas

respondido por: Anônimo
0

Resposta:

Explicação passo-a-passo:

A)

(20-3)+(7+5)=

= 17+12

= 29

B)

50+{[15+(3-9)+1]}=

= 50+{[15+(-6)+1]}

= 50+{[15-6+1]}

= 50+{[9+1]}

= 50+{10}

= 60

C)

15-(7+2)-8=

= 15-(9)-8

= 15-9-8

= 6-8

= -2

D)

18+(9-15)-8=

= 18+(-6)-8

= 18-6-8

= 18-14

= 4

E)

7-[4+(3-5)]=

=7-[4+(-2)]

=7-[4-2]

= 7 - [2]

= 7 - 2

= 5

F)

{5 - 532-(50-20]}=

={- 527-(30)}

= - 527-30

= - 557

G)

{16-[12+(20-25)]}=

= {16-[12+(-5)]}

= {16-[12-5}

= {16-[7]}

= 16-7

= 9

H)

10-{30+[4-(5+2)]}=

= 10- {30+[4 - (7)]}

= 10 - {30+[4-7]}

= 10 - {30+[-3]}

= 10 - {30-3}

= 10 - {27}

= 10-27

= - 17

I)

= {-2+[3-0-(8+1)]-10}

= {-2+[3-(9)]-10}

= {-2+[3-9] - 10}

= {-2+[-6]-10]

= {-2-6-10}

= {-8-10}

= - 18

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