Question

(x-5)ao quadrado=4(x-2)

Answer 1

Boa Noite!

$(5-x)^{2} =4(x-2) \\ \\ 25-10x+ x^{2} =4x-8 \\ \\ x^{2} -14x+33=0 \\ \\ \frac{-(-14)+- \sqrt{14^{2}-4*1*33 } }{2*1} \\ \\ \frac{14+- \sqrt{64} }{2} \\ \\ \frac{14+-8 }{2} \\ \\ \left \{ {{x_{1} = \frac{14+8}{2}=11 } \atop { x_{2} =\frac{14-8}{2}=3}} \right.$